For each projectile particle, write the point on the curve.
Eg. ( Ux * t , Uy - at) and (Vx * t , Vy-a*t).
Disance between these two particles wil be calculated by using distance formula .
d = ((x2 - x1)^2 + (Y2- y1)^2 ) ^ 1/2
Now diffrentiate and put this function = 0 to find maxima / minima.
Thank you...can u please explain it using an example??
(1) the initial speeds are equal
(2) the angles of projections are unequal with one of them being >45 degrees
(3) the projectiles land on each others launching point
the minimum distance between the rocks during their flight will be
r min = d.[(1 - sin2θ) / 2] 1/2 = v 2 (sin2θ / g).[(1 - sin2θ) / 2] 1/2
(calculated by steps written in previous answer)
v = launch speed
θ = angle of projection of any one projectile
d = v2(sin2θ / g) = range of projectile