## is the minimum distance between two relative projectiles at their respective max heights??

17-Nov-2015 10:20 AM
~2

0

Not always.
For each projectile particle, write  the point on the curve.
Eg.  ( Ux * t ,  Uy - at) and (Vx * t ,  Vy-a*t).
Disance between these two particles wil be calculated by using distance formula .
d = ((x2 - x1)^2 + (Y2- y1)^2 ) ^ 1/2
Now diffrentiate and put this function = 0 to find maxima / minima.

17-11-2015 12:12
~48

0

Thank you...can u please explain it using an example??

17-11-2015 23:27
~2

0

If

(1) the initial speeds are equal

(2) the angles of projections are unequal with one of them being >45 degrees

(3) the projectiles land on each others launching point

then,

the minimum distance between the rocks during their flight will be

r min = d.[(1 - sin2θ) / 2] 1/2 =  v 2 (sin2θ / g).[(1 - sin2θ) / 2] 1/2

(calculated by steps written in previous answer)

here,

v = launch speed

θ = angle of projection of any one projectile

d = v2(sin2θ / g) = range of projectile

18-11-2015 18:01
~48