a particle of mass 'm' is projected with a velocity v making angle 30 degree with horizontal. the magnitude of angular momentum of th projectile about the point of projection when it is at its maxim height h is:

08-Dec-2016 3:42 PM

Answers (1)


max height ,H= v2sin2θ/2g

velocity at max height = ux= vcosθ

angular momentum= muxH

Put θ =300 and get the answer.

13-12-2016 21:22

You need to Log in to submit an answer

  • Answer Questions and earn reputation points