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a particle of mass 'm' is projected with a velocity v making angle 30 degree with horizontal. the magnitude of angular momentum of th projectile about the point of projection when it is at its maxim height h is:



08-Dec-2016 3:42 PM
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Answers (1)


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max height ,H= v2sin2θ/2g

velocity at max height = ux= vcosθ

angular momentum= muxH

Put θ =300 and get the answer.



13-12-2016 21:22
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