Is x/(√x+1 - √x) continuous at x=0?

As i have solved at x--> 0— f(x),

there is a negative value in root which means its would be an imaginary value and hence it is discontinuous and non differentiable at x=0.

But the answer given is different.

Please explain

16-Oct-2016 10:03 PM

Answers (1)


If you put 0 in that expression, as x tends to 0, you will get 0. So, it is continuos at 0.

You can evaluate this limit by putting zero in this expression directly, because at x tends to 0 it is not an indeterminate form. You can also rationalize this expression first, and then evaluate the expression at x tends to 0.

I would say check your calculation. On putting 0, you don't get an imaginary value. 0 is clearly in the domain of this function.

29-12-2016 12:35

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