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The charge on 500cc of water due to proton will be

0

We can take fair approximation:

500 cc = 500 ml = 500 gm

so,

the number of moles of water = 500 / atomic weight = 500 / 18 = 27.78 moles.

thus, the number of molecules would be = number of moles X Avagadro's Number

or

the total number of molecules = 27.78 X 6.023 X 10^{23} = 1.67 X 10^{25}

and each water molecule has 10 protons in it. thus total number of protons in 500 cc of water would be

= total number of molecules X 10

= 1.67 X 10^{26} protons

thus, the total protonic charge = number of protons X protonic charge

or Q = ne

or Q = 1.67 X 10^{26} X 1.6 X 10^{-19} C

Thus, the required answer is the total charge due to protons in 500cc of water

**Q = 2.67 X 10** ^{ 7 } ** C **